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Question #c419f

1 Answer

A. S. Adikesavan

Mar 13, 2016

$x = \frac{ln c}{a - b}$ $x = ln c / ( a - b )$

Explanation:

$e^{(a - b) x} = c$ $e^((a-b)x) = c$
Use ${ln e}^{n} = n$ $ln e^n = n$
This is valid for any c > 0.
$e^{k x} > 0$ $e^(kx) > 0$ , for all k and x.

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