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Question #4f1cd

1 Answer

Sep 9, 2016

I assume this is #f(x) = x^2+1#, in which case the number you want is #1/2#.

Explanation:

The #c# in the conclusion of MVT is every number in #(0,1)# that satifies #f'(x) = (f(1)-f(0))/(1-0)#.

Solving

#2x = (2 - 1)/(1-0)#, we fet

#x = 1/2#.

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