How do you construct polynomial equations with the given roots?

1. 2, 4 and 7.
2. 5 and 3.

1 Answer
Aug 11, 2017

1. x3+x234x+56=0

2. x35x23x+15=0

Explanation:

Note that if a polynomial in x has a zero a then it has a factor (xa) and vice versa.


For question 1 we can construct a polynomial:

f(x)=(x2)(x4)(x+7)=x3+x234x+56

Any polynomial with these zeros will be a multiple (scalar or polynomial) of this f(x).

So the polynomial equation:

x3+x234x+56=0

has roots 2, 4 and 7.


For question 2 we can multiply out (x5)(x3) but this will result in a polynomial with irrational coefficients:

(x5)(x3)=x2(5+3)x+53

If - as is probably the case - we want a polynomial with integer coefficients, then we also need the rational conjugate 3 to be a zero and (x+3) a factor.

Then we can define:

g(x)=(x5)(x3)(x+3)=(x5)(x23)=x35x23x+15

Any polynomial with these zeros will be a multiple (scalar or polynomial) of this g(x).

So the polynomial equation:

x35x23x+15=0

has roots 5, 3 and 3.