When hydrochloric acid reacts with sodium hydroxide, which reagent is in excess?

1 Answer
anor277
Feb 23, 2016

Consider the reaction:
#HCl(aq) + NaOH(aq) rarr NaCl(aq) + H_2O(l)#

Explanation:

The reagent in excess is whichever reagent was in the majority. The stoichiometry of the reaction was 1:1. Now you were supplied with equal volumes of acid and base with equal concentrations. Neither the volume nor the concentration of each reagent were entirely accurate. The reaction unequivocally tells us that 1 equivalent of aqueous sodium hydroxide reacts with 1 equiv aqueous sodium hydroxide.

How many moles of acid are there in #50# #cm^3# of #1.00# #mol*L^-1# #HCl#? It is the same number as the moles of base in #50# #cm^3# of #1.00# #mol*L^-1# #NaOH#

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