You have #28*g# dinitrogen, and #24*g# of dihydrogen. What is the limiting reagent with respect to ammonia formation?

1 Answer
anor277
Apr 18, 2016

Dihydrogen is in excess, so dinitrogen is the limiting reagent. Approx. 34 g of ammonia can be produced.

Explanation:

#N_2(g) + 3H_2(g) rarr 2NH_3(g)#

You have approx #1# mol #N_2# and #12# mol #H_2#. If you assume 100% yield, 2 mol ammonia should result. Of course, the actual production of ammonia gets nowhere near these yields.

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