You have 28*g dinitrogen, and 24*g of dihydrogen. What is the limiting reagent with respect to ammonia formation?

1 Answer
Apr 18, 2016

Dihydrogen is in excess, so dinitrogen is the limiting reagent. Approx. 34 g of ammonia can be produced.

Explanation:

N_2(g) + 3H_2(g) rarr 2NH_3(g)

You have approx 1 mol N_2 and 12 mol H_2. If you assume 100% yield, 2 mol ammonia should result. Of course, the actual production of ammonia gets nowhere near these yields.