Question #423ae

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Question #423ae

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Answer 1 · 2016-02-16T00:38:36

I got $604 μ L$ $604muL$
(hope it is understandable)

Explanation:

Ok, let us see:
$1 dg = \frac{1}{10} g = 0.1 g$ $1"dg"=1/10g=0.1g$
so
$1.45 dg = \frac{1.45}{10} g = 0.145 g$ $1.45"dg"=1.45/10g=0.145g$

so your cork will have a volume:
$density = \frac{mass}{volume}$ $"density"="mass"/"volume"$
$volume = \frac{mass}{density} = \frac{0.145}{0.240} = 0.604 m L$ $"volume"="mass"/"density"=0.145/0.240=0.604mL$

But:

$1 μ L = \frac{1 ml}{1, 000} = 0.001 m L$ $1muL=(1"ml")/(1,000)=0.001mL$
and as a consequence:
$1 m L = \frac{1}{0.001} μ L$ $1mL=1/0.001muL$
so in our case we get:
$\frac{0.604}{0.001} = 604 μ L$ $0.604/0.001=604muL$

Remember that:
$1 μ L = \frac{1}{1, 000, 000} L = 0.000001 L$ $1muL=1/(1,000,000)L=0.000001L$
$1 m L = \frac{1}{1, 000} L = 0.001 L$ $1mL=1/(1,000)L=0.001L$

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Question #423ae

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