How many structures are there for "XeF"_5^(+)XeF+5?
1 Answer
Aug 14, 2017
There's only one structure.
"XeF"_5^(+)XeF+5 has contributions from...
"Xe": " "" "" 8 valence electrons"Xe: 8 valence electrons "F": " "" "5 xx 7F: 5×7 "valence electrons"valence electrons (+): " "-1(+): −1 "valence electrons"valence electrons
and thus has
- Start with the skeletal structure and that uses
5 xx 2 = ul10 of them. - Each fluorine atom can hold three lone pairs, i.e.
3 xx 2 xx 5 = ul30 accounted for. - That leaves
ul2 electrons for one lone pair on the"Xe" .
The axial-equatorial bond angles are IDEALLY
But of course, the lone pair on