Question #e0b9c

1 Answer
Feb 5, 2016

Reactions "(i)" and "(ii)".

Explanation:

I admit that I've never come across reactions "(iii)" and ("iv"), so right from the start I eliminated those two as possible valid answers.

Now, the first reaction will indeed produce carbon monoxide, "CO".

When heated with concentrated sulfuric acid, potassium ferrocianide, "K"_4"Fe"("CN")_6, will produce

  • potassium sulfate, "K"_2"SO"_4
  • iron(II) sulfate, "FeSO"_4
  • ammonium sulfate, ("NH"_4)_2"SO"_4
  • carbon monoxide, "CO"

The balanced chemical equation for this reaction looks like this

"K"_4"Fe"("CN")_text(6(aq]) + 6"H"_2"SO"_text(4(aq]) + 6"H"_2"O"_text((l]) -> 2"K"_2"SO"_text(4(aq]) + "FeSO"_text(4(aq]) + 3("NH"_4)_2"SO"_text(4(aq]) + 6"CO"_text((g]) uarr

Now, I assume that the second reaction is actually the decomposition of nickel tetracarbonyl, "Ni"("CO")_4, since no other reactants are given.

Upon heating, nickel tetracarbonyl will decompose to form nickel metal and carbon monoxide. The balanced chemical equation for this reaction looks like this

"Ni"("CO")_text(4(g]) stackrel(color(red)(Delta)color(white)(aa))(->) "Ni"_text((s]) + 4"CO"_text((g])

This reaction is part of the Mond process, a technique used to extract nickel from impure nickel.

As far as the other two reactions go, I really don't see what could be going on there.

The only way I can think off to getting carbon monoxide from a zinc compound is by heating zinc oxide, "ZnO", with carbon. The reaction will produce carbon monoxide and zinc vapor

"ZnO"_text((s]) + "C"_text((s]) stackrel(color(red)(Delta)color(white)(aa))(->) "Zn"_text((g]) + "CO"_text((g])

I assume that the last reaction involves heating magnesium carbonate with zinc metal. I don't think that adding zinc in there could change the fact that magnesium carbonate decomposes to form magnesium oxide, "MgO", and carbon dioxide, "CO"_2.