Question #7396d

1 Answer
Jun 23, 2016

Option=1

Explanation:

ZnCl_2" dissolves in excess NaOH"
"as well as in excess "NH_3

In aqueous solution the reactions occuring can be represented by following equations.

For NaOH

ZnCl_2(aq)+2NaOH(aq)=Zn(OH)_2darr+2NaCl(aq)

Zn(OH)_2+2NaOH(aq)=Na_2ZnO_2("soluble")+2H_2O

For NH_3(aq)=NH_4OH

ZnCl_2(aq)+2NH_4OH(aq)=Zn(OH)_2darr+2NH_4Cl(aq)

Zn(OH)_2+4NH_4OH(aq)=Zn(NH_3)_4(OH)_2("soluble")+4H_2O