What is the number of ethyl alcohol molecules in a $22.26*g$ mass?

Question

2028 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-06T21:18:04

Approx. half a mole. Therefore approx. $1/2$ Avogadro's number.

Moles of ethanol $=$ $(22.26*g)/(46.07*g*mol^-1)$ . This molar quantity represents a fraction of Avogadro's number.

In $1$ $mol$ of stuff there are $N_A$ individual items of that stuff, where $N_A$ $=$ $6.022xx10^23$ .

So the answer $=$ $(22.26*cancel(g))/(46.07*cancel(g)*cancel(mol^-1))$ $xx$ $6.022xx10^23*cancel(mol^-1)$ $=$ $??$

We get a dimensionless number, as is required for a number.

What is the number of ethyl alcohol molecules in a 22.26*g22.26*g mass?