569 g salt water solution is added to a beaker. If the solution has a density of 1.19 g/mL, what is the volume of this solution?

1 Answer
Sep 23, 2016

Approx. 475*mL

Explanation:

rho,"density" = "Mass"/"Volume"

Thus, "volume" = "Mass"/rho = (569*cancelg)/(1.19*cancelg*mL^-1) = ??mL.

Note the dimensional consistency. I wanted a volume; and the units of the calculation cancelled to give me an answer in "millilitres" (or rather in 1/(mL^-1)=mL). This persuades me that I set up the problem correctly; it's all too east to make a mistake.