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Question #ba858

1 Answer

Jan 11, 2016

#1510 gC_3H_8#

Explanation:

From the energy released and the molar enthalpy we can find the number of mole of propane that needs to be used;

#?mol C_3H_8=76000cancel(KJ)xx(1molC_3H_8)/(2219cancel(KJ))=34.25 molC_3H_8#

To find the mass of propane needed:

#?gC_3H_8=34.25cancel("mol "C_3H_8)xx(44.10gC_3H_8)/(1cancel("mol "C_3H_8))=1510 gC_3H_8#

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