Given the complex ${[C r {(N H_{3})}_{5} X]}_{5}^{2 +}$ $[Cr(NH_3)_5X]^(2+)$ , how would formulate its substitution reactions?

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Given the complex ${[C r {(N H_{3})}_{5} X]}_{5}^{2 +}$ $[Cr(NH_3)_5X]^(2+)$ , how would formulate its substitution reactions?

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Answer 1 · 2015-12-29T11:36:41

Chromium $(I I I)$ $(III)$ complexes are generally octahedral. We simply replace one of the primary ligands for one of the counterions and conserve mass and charge.

Explanation:

${[C r {(N H_{3})}_{5} C l]}_{5}^{2 +} (a q) + N O_{3}^{-} ⇌ {[C r {(N H_{3})}_{5} (O N O_{2})]}_{5}^{2 +} (a q) + C l^{-}$ $[Cr(NH_3)_5Cl]^(2+)(aq) + NO_3^(-) rightleftharpoons [Cr(NH_3)_5(ONO_2)]^(2+)(aq) + Cl^-$

Alternatively:

${[C r {(N H_{3})}_{5} C l]}_{5}^{2 +} (a q) + N O_{3}^{-} ⇌ {[C r {(N H_{3})}_{4} (O N O_{2}) C l]}_{4}^{+} (a q) + N H_{3} (a q)$ $[Cr(NH_3)_5Cl]^(2+)(aq) + NO_3^(-) rightleftharpoons [Cr(NH_3)_4(ONO_2)Cl]^(+)(aq) + NH_3(aq)$

These equilibria would be going on all the time in aqueous solution; including the replacement of ammine or chloro ligands for water (below). What crystallizes out is the least soluble species; whatever this is.

${[C r {(N H_{3})}_{5} C l]}_{5}^{2 +} (a q) + O H_{2} ⇌ {[C r {(N H_{3})}_{5} (O H_{2})]}_{5}^{3 +} (a q) + C l^{-}$ $[Cr(NH_3)_5Cl]^(2+)(aq) + OH_2 rightleftharpoons [Cr(NH_3)_5(OH_2)]^(3+)(aq) + Cl^-$

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Given the complex ${[C r {(N H_{3})}_{5} X]}_{5}^{2 +}$ $[Cr(NH_3)_5X]^(2+)$ , how would formulate its substitution reactions?

1 Answer

Explanation:

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Given the complex [Cr(NH3)5X]2+[Cr(NH_3)_5X]^(2+), how would formulate its substitution reactions?

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Explanation:

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Given the complex ${[C r {(N H_{3})}_{5} X]}_{5}^{2 +}$ $[Cr(NH_3)_5X]^(2+)$ , how would formulate its substitution reactions?