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Question #38499

1 Answer

Nov 22, 2015

#0.0835"mol/l"#

Explanation:

#H_2SO_(4(aq))+2NaOH_((aq))rarrNa_2SO_(4(aq))+2H_2O_((l))#

#nNaOH=0.0599xx0.34=0.02#

#:.nH_2SO_4=0.02/2=0.01#

#c=n/v#

#:.[H_2SO_4]=0.01/0.01198=0.835"mol/l"#

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