Question #55acc
1 Answer
Mar 13, 2016
Explanation:
Recall that the formula for
#color(blue)(|bar(ul(color(white)(a/a)pH=-log[H^+]color(white)(a/a)|)))#
where:
Determining the pH
To find the pH, substitute your known values into the
#pH=-log[H^+]#
#pH=-log(0.000841M)#
#color(green)(|bar(ul(color(white)(a/a)pH~~3.08color(white)(a/a)|)))#