Question #ee719

1 Answer
P dilip_k
Feb 19, 2016

calculation may be done as follows

Explanation:

0.36 M #H_2SO_4# means 0.72 N #H_2SO_4#
25 mL of this solution contains #25*0.72/1000# gmEquivalent acid = 0.018 gm Equivalent acid
So for neutralization same gm Equivalent #NaHCO_3#will be needed
Equivalent mass of #NaHCO_3#
= Formula mass/1
=23+1+12+3x16 =84
hence reqd amount of salt = 0.018x84 g=1.512 g

pl, inform if error exists

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