Given constant volume, what pressure would #50*atm# of gas at #0# #""^@C#, develop at a temperature of #300# #""^@C#?

1 Answer
anor277
Nov 14, 2015

Gay Lusaac's law holds that at constant volume, #((P_1)/T_1 = (P_2)/T_2)# (i.e. pressure is proportional to temperature at constant volume).

Explanation:

So, #P_2# #=# #(P_1T_2)/T_1# #=# #(50.0*atmxx273K)/(573K)# #=#

#?? atmospheres#

This is reasonable on the basis that we would expect a given quantity of gas to exert less pressure at lower temperature. Note that I converted the temperature to the Kelvin scale in order to avoid multiplying by #0#.

Related questions
See all questions in Gay Lussac's Law
Impact of this question
1833 views around the world
You can reuse this answer
Creative Commons License