Question #943a4

Question

Question #943a4

1 Answer

Impact of this question

3172 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-18T19:01:24

$d_{m} = \frac{8 \cdot d_{1} \cdot d_{2}}{5 \cdot d_{1} + 3 \cdot d_{2}}$ $d_m=(8*d_1*d_2)/(5*d_1+3*d_2)$

Explanation:

$\frac{m_{1}}{m_{2}} = \frac{3}{5} m_{1} = \frac{3}{5} m_{2}$ $m_1/m_2=3/5" "color(red)(m_1=3/5m_2)$
$d_{1} = \frac{m_{1}}{v_{1}} v_{1} = \frac{m_{1}}{d_{1}} v_{1} = \frac{\frac{3}{5} m_{2}}{d_{1}}$ $d_1=m_1/v_1" "color(green)(v_1=m_1/d_1)" "color(green)(v_1)=(color(red)(3/5m_2))/(color(green)(d_1))$
$d_{2} = \frac{m_{2}}{v_{2}} v_{2} = \frac{m_{2}}{d_{2}}$ $d_2=m_2/v_2" "color(blue)(v_2=m_2/d_2)$

$d_{m} = \frac{m_{1} + m_{2}}{v_{1} + v_{2}} density equation for mixture$ $d_m=(color(red)(m_1)+m_2)/(v_1+v_2)" density equation for mixture"$

$d_{m} = \frac{\frac{3}{5} m_{2} + m_{2}}{\frac{\frac{3}{5} m_{2}}{d_{1}} + \frac{m_{2}}{d_{2}}}$ $d_m=(3/5m_2+m_2)/((3/5 m_2)/d_1+m_2/d_2)$

$d_{m} = \frac{8 \frac{m_{2}}{5}}{\frac{(\frac{3}{5} m_{2} d_{2}) + m_{2} d_{1}}{d_{1} \cdot d_{2}}}$ $d_m=(8m_2/5)/(((3/5m_2d_2)+m_2d_1)/(d_1*d_2))$

$d_{m} = \frac{8 \frac{m_{2}}{5}}{\frac{(3 m_{2} \cdot d_{2} + 5 m_{2} \cdot d_{1})}{5 d_{1} \cdot d_{2}}}$ $d_m=(8m_2/5)/(((3m_2*d_2+5m_2*d_1))/(5d_1*d_2))$

$d_m=8 cancel(m_2)/cancel(5) *(cancel(5)*d_1*d_2)/(cancel(m_2)(3*d_2+5*d_1))$

$d_m=(8*d_1*d_2)/(5*d_1+3*d_2)$

Science

Math

Humanities

... and beyond

Question #943a4

1 Answer

Explanation:

Related questions

Impact of this question