Question #ccb14

1 Answer
Trevor Ryan.
Oct 31, 2015

0,1833mol.
1,104xx10^23 particles.
71,11% oxygen by mass.

Explanation:

Moles = Mass divided by molar mass.
therefore n=(16,5g)/(2xx1+12xx2+16xx4g//mol)=0,1833mol

One mole contains an Avagadro number of particles, ie 6,023xx10^23 particles.
Hence by ratio and proportion, 0,1833 moles will contain
0,1833xx6,023xx10^23=1,104xx10^23 particles.

In 1 mole of H_2C_2O_4, which has a mass of 90g, exactly 64g of this 90g is oxygen. this corresponds to a percent of 64/90xx100=71,11%.

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