Which molecule has the most number of lone pairs: $C l - C H_{3}$ $Cl-CH_3$ ; $C O_{2}$ $CO_2$ ; $H_{2} N - N H_{2}$ $H_2N-NH_2$ ; $H_{4} N^{+}^{-} C \equiv N$ $H_4N^+""^(-)C-=N$ ...?

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Answer 1 · 2017-02-18T04:18:07

Of lone pairs, surely it's carbon dioxide?

$H_{3} C - C l$ $H_3C-Cl$ has 3 lone pairs. Where are they?

$O = C = O$ $O=C=O$ has 4 oxygen-centred lone pairs.

$H_{2} N - N H_{2}$ $H_2N-NH_2$ has 2 nitrogen-centred lone pairs.

$H_{4} N^{+}^{-} C \equiv N$ $H_4N^(+)""^(-)C-=N$ , has 2 lone pairs, one on the carbon, and one on the nitrogen.

Which molecule has the most number of lone pairs: Cl−CH3Cl-CH_3; CO2CO_2; H2N−NH2H_2N-NH_2; H4N+−C≡NH_4N^+""^(-)C-=N...?