Question #7d62e

1 Answer
Gió
Oct 27, 2015

Assuming #15,000cm^3# of wood I got: #12,750g#

Explanation:

Kate, remember that you need to include the units as well!
For example you have a volume of #15000#....#cm^3#?

You may use a table to find the DENSITY of your material (basically how much stuff fits into a given volume of this stuff); these tables can be found in textbooks, websites...as for example:

http://www.nyu.edu/pages/mathmol/textbook/density2.html

Density tells you the amount of mass in grams that fits into a volume of #1 cm^3#....for wood #0.85g/(cm^3)#

So: #"density"="mass"/"volume"# and rearranging:

#"mass"="density"xx"volume"#

If you have #15000cm^3# of wood then:

#"mass"=0.85xx15000=12,750g#
If you have different types of wood (cedar, fir, pine...etc) you can change the corresponding value of density and evaluate the new value of mass.

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