Question #444cf

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Question #444cf

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Answer 1 · 2015-10-18T18:29:49

The reaction produces sodium carbonate, water, and carbon dioxide.

Explanation:

Sulfuric acid, $H_{2} {SO}_{4}$ $"H"_2"SO"_4$ , will react with sodium carbonate, ${Na}_{2} {CO}_{3}$ $"Na"_2"CO"_3$ , to form sodium sulfate, ${Na}_{2} {SO}_{4}$ $"Na"_2"SO"_4$ , and carbonic acid, $H_{2} {CO}_{3}$ $"H"_2"CO"_3$ .

In aqueous solution, carbonic acid actually exists in equilibrium with water and carbon dioxide, ${CO}_{2}$ $"CO"_2$ .

$H_{2} {CO}_{3(aq]} ⇌ H_{2} O_{(l]} + {CO}_{2(aq]}$ $"H"_2"CO"_text(3(aq]) rightleftharpoons "H"_2"O"_text((l]) + "CO"_text(2(aq])$

The balanced chemical equation for this reaction will looks like this

$H_{2} {SO}_{4(aq]} + {Na}_{2} {CO}_{3(s]} \to {Na}_{2} {SO}_{4(aq]} + H_{2} O + {CO}_{2}      H_{2} {CO}_{3(aq]}$ $"H"_2"SO"_text(4(aq]) + "Na"_2"CO"_text(3(s]) -> "Na"_2"SO"_text(4(aq]) + overbrace("H"_2"CO"_text(3(aq]))^(color(blue)("H"_2"O" + "CO"_2))$

The reaction can thus be written as

$H_{2} {SO}_{4(aq]} + {Na}_{2} {CO}_{3(s]} \to {Na}_{2} {SO}_{4(aq]} + H_{2} O_{(l]} + {CO}_{2(g]} ↑ ⏐$ $"H"_2"SO"_text(4(aq]) + "Na"_2"CO"_text(3(s]) -> "Na"_2"SO"_text(4(aq]) + "H"_2"O"_text((l]) + "CO"_text(2(g]) uarr$

The carbon dioxide will bubble out of solution.

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Question #444cf

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