Question #f4442

1 Answer
le experz
Oct 4, 2015

pH + pOH = 14

Explanation:

At 25 °C, dissociation constant of water, #K_w#, is equal to #1.0×10^{−14}# #({mol}/L)^2#

#K_w=[H_3O^+][OH^-]#
#log(K_w)=log([H_3O^+][OH^-])#
#log(K_w)=log([H_3O^+]) + log[OH^-])#
#-14=-pH -pOH#
#14=pH +pOH#

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