Question #f4442

1 Answer
le experz
Oct 4, 2015

pH + pOH = 14

Explanation:

At 25 °C, dissociation constant of water, K_w, is equal to 1.0×10^{−14} ({mol}/L)^2

K_w=[H_3O^+][OH^-]
log(K_w)=log([H_3O^+][OH^-])
log(K_w)=log([H_3O^+]) + log[OH^-])
-14=-pH -pOH
14=pH +pOH

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