How does lead sulfide react with oxygen gas to form #PbO#, and #SO_2#? Chemistry Electrochemistry Balancing Redox Equations Using the Oxidation Number Method 1 Answer anor277 Oct 4, 2015 #PbS + 3/2O_2 rarr PbO + SO_2# Explanation: Elemental oxygen is reduced (#0 rarr -II#) and sulfur is oxidized (#-II rarr +IV#). The oxidation state of the metal is unchanged. Answer link Related questions How do you balance redox reactions in basic solution? How do you balance redox equations by oxidation number method? How do you balance redox equations in acidic solutions? What is the oxidation number method? What are some examples of balancing redox equations using the oxidation number method? Why is the oxidation number method useful? Is it necessary to break the equation into half reactions in the oxidation number method? What is the difference between the oxidation number method and the ion-electron method? Can you balance the equation using the oxidation states method MnO2+Al--->Mn+Al2O3? How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... See all questions in Balancing Redox Equations Using the Oxidation Number Method Impact of this question 3550 views around the world You can reuse this answer Creative Commons License