How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

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How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

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Answer 1 · 2015-09-26T23:25:40

$DBE=2$

In other words, the molecule has 2 degrees of unsaturation.

Explanation:

The molecular formula of 2,2,3,3-tetramethyl-4-octyne is $C_12H_22$

The general formula for calculating the double bond equivalent (DBE) is:

$DBE=C-H/2+N/2+1$

where, $C$ is the number of carbon atoms, $H$ is the number of hydrogen and halogen atoms, and $N$ is the number of nitrogen atoms if there is any in the molecule.

Therefore, in this case:

$DBE=12-(22)/2+(0)/2+1=2$

It is logic to find $DBE=2$ since we have two $pi$ bonds in a triple bond.

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How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

1 Answer

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