How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

Question

How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

1 Answer

Impact of this question

3503 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-26T23:25:40

$D B E = 2$ $DBE=2$

In other words, the molecule has 2 degrees of unsaturation.

Explanation:

The molecular formula of 2,2,3,3-tetramethyl-4-octyne is $C_{12} H_{22}$ $C_12H_22$

The general formula for calculating the double bond equivalent (DBE) is:

$D B E = C - \frac{H}{2} + \frac{N}{2} + 1$ $DBE=C-H/2+N/2+1$

where, $C$ $C$ is the number of carbon atoms, $H$ $H$ is the number of hydrogen and halogen atoms, and $N$ $N$ is the number of nitrogen atoms if there is any in the molecule.

Therefore, in this case:

$D B E = 12 - \frac{22}{2} + \frac{0}{2} + 1 = 2$ $DBE=12-(22)/2+(0)/2+1=2$

It is logic to find $D B E = 2$ $DBE=2$ since we have two $π$ $pi$ bonds in a triple bond.

Science

Math

Humanities

... and beyond

How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?

1 Answer

Explanation:

Related questions

Impact of this question