Question #5650b

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Question #5650b

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Answer 1 · 2015-09-17T10:07:09

Sodium forms three anhydrous monophosphates with the three phosphates.

Explanation:

Sodium and the phosphate anion can actually only form one compound, trisodium phosphate, ${Na}_{3} {PO}_{4}$ $"Na"_3"PO"_4$ .

The other two compounds you're probably referring to are actually formed with the dihydrogen phosphate, $H_{2} {PO}_{4}^{-}$ $"H"_2"PO"_4^(-)$ , and hydrogen phosphate, ${HPO}_{4}^{2 -}$ $"HPO"_4^(2-)$ , anions.

Moreover, sodium can form monophosphates and polyphosphates, in several anhydrous and hydrate forms, so I will assume that you're interested in the anhydrous monophosphates here.

monosodium phosphate

This compound is formed when one sodium cation, ${Na}^{+}$ $"Na"^(+)$ , combines with one dihydrogen phosphate anion, $H_{2} {PO}_{4}^{-}$ $"H"_2"PO"_4^(-)$ .

The salt dissociates completely in aqueous solution

${NaH}_{2} {PO}_{4(aq]} \to {Na}_{(aq]}^{+} + H_{2} {PO}_{4(aq]}^{-}$ $"NaH"_2"PO"_text(4(aq]) -> "Na"_text((aq])^(+) + "H"_2"PO"_text(4(aq])^(-)$

disodium phosphate

This compound is formed when two sodium cations combine with one hydrogen phosphate anion, ${HPO}_{4}^{2 -}$ $"HPO"_4^(2-)$ .

${Na}_{2} {HPO}_{4(aq]} \to 2 {Na}_{(aq]}^{+} + {HPO}_{4(aq]}^{2 -}$ $"Na"_2"HPO"_text(4(aq]) -> 2"Na"_text((aq])^(+) + "HPO"_text(4(aq])^(2-)$

trisodium phosphate

This time, you have three sodium cations and one phosphate anion, ${PO}_{4}^{3 -}$ $"PO"_4^(3-)$ .

${Na}_{3} {PO}_{4(aq]} \to 3 {Na}_{(aq]}^{+} + {PO}_{4(aq]}^{3 -}$ $"Na"_3"PO"_text(4(aq]) -> 3"Na"_text((aq])^(+) + "PO"_text(4(aq])^(3-)$

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Question #5650b

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