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Question #0a95e

1 Answer

Jul 1, 2015

The answer is B

Explanation:

Relative atomic mass of #Al=27# and #Cl=35.5#
To form #AlCl_3# you need these in the ratio:

#(m(Cl))/(m(Al))= (3*35.5)/(1*27)=106.5/27->#

#m(Cl)=106.5/27*m(Al)=106.5/27*13.5=53.2g#

The mass of the #AlCl_3#
#m(AlCl_3)=13.5+53.2=66.7g#

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