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Answer 1 · 2015-06-27T21:02:06

The reactive force exerted on the body will be equal to 25 N.

An equilateral triangle has all three internal angles equal to $60^{\circ}$ $60^@$ .

This means that, regardless on which side your triangle stands on, its other two sides will form $60^{\circ}$ $60^@$ angles with the horizontal.

![https://en.wikipedia.org/wiki/Equilateral_triangle]( useruploads.socratic.org )

Either side of the triangle will thus be equivalent to an inclined plane

![http://www.quora.com/Why-is-normal-force-on-a-banked-curve-different-from-normal-force-on-an-inclined-plane](https://d2jmvrsizmvf4x.cloudfront.net/tPt5USKTAWodWFKGtKAA_main-qimg-53327b3c0b795f33aeba2042e688631a)

The normal force exerted on the body will be equal to

$N = m g \cdot cos (θ)$ $N = mg * cos(theta)$ , where

$m$ $m$ - the mass of the body;
$g$ $g$ - the gravitational acceleration;
$θ$ $theta$ - the angle formed by the inclined plane with the horizontal.

Plug your values into the above equation and solve for $N$ $N$ (assume $g$ $g$ to be equal to $10 {m/s}^{2}$ $10"m/s"^2$ )

$N = 5 kg \cdot 10 \frac{m}{s^{2}} \cdot cos (60^{\circ})$ $N = "5 kg" * 10"m"/"s"^2 * cos(60^@)$

$N = 50 underbrace(("kg" * "m")/"s"^2)_(color(blue)("=Newton")) * 1/2 = color(green)("25 N")$