Question #8c623

1 Answer
Gió
Jun 9, 2015

1) o->p
Av(speed)=20m/s
Av(velocity)=20 m/s
2) o->p->o
Av(speed)=20m/s
Av(velocity)=0 m/s

Explanation:

I considered only the distance op (I didn't use oq).
The average velocity is the change of position x, indicated as Deltax (known as displacement), divided by the corresponding change in time Deltat.
v_(av)=(Deltax)/(Deltay)=(x_f-x_i)/(t_f-t_i)
Where x_i is the position at o that I considered the origin x_1=0.

The average speed s is a little bit more subtle...it is the total distance travelled, d, divided by the time needed.
s_(av)=d/t

So you get:
enter image source here

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