Question #536ac

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Answer 1 · 2015-05-20T22:25:08

86.8kJ

1 mole requires 40.5 kJ

#M_r= (12xx2) +(5xx1) +16 + 1)=46#

Approx Ar values used so I'll say I mole weighs 46.0g.

You should use the values you are given and quote the significant figures accordingly.

So:

46.0g requires 40.5kJ

1g requires 40.5/46.0 kJ

98.6g requires (40.5/46.0) x 98.6 = 86.8g