What is the percentage of ammonium ions in ammonium dichromate?

1 Answer
Meave60
May 6, 2015

The formula unit for ammonium dichromate is #"(NH"_4)_2"Cr"_2"O"_7"#, and has a molar mass of #252.07 "g/mol"#.

The ammonium ion, #"NH"_4^+"#, is the cation, and its molar mass is #18.039 "g/mol"#. Since there are two moles of ammonium cations in one mole of ammonium dichromate, we multiply #18.039 "g/mol"xx2 #, which is equal to #36.078 "g/mol"#.

To find the percentage of ammonium cations in ammonium dichromate, divide the total mass of the ammonium cations by the molar mass of ammonium dichromate and multiply times 100.

#"%NH"_4^+=(36.078 "g/mol")/(252.07 "g/mol")xx100=14.313%#

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