Notice that you have a #1:color(red)(2)#mole ratio between sulfuric acid and sodium hydroxide, which implies that, regardless of how many moles of sulfuric acid you have, you need twice as many moles of sodium hydroxide in order for the base to not act as a limiting reagent.
Comparing the number of moles of sulfuric acid and of sodium hydroxide you add will tell how which one of the two is the limiting reagent and which one is the excess reactant.
Use the two solutions' molarity to determine the number of moles of each species added
Since you have a #1:1#mole ratio between sulfuric acid and sodium sulfate, the number of moles of the latter produced by the reaction will be equal to the number of moles of the former that react