Question #4cb37

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Question #4cb37

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Answer 1 · 2015-04-27T16:18:03

Vertices (0,5) and (0, -5), Focii (0,4) and (0-4)

Compare the given equation with the standard equation of an ellipse with center at (0,0). It is $\frac{x^{2}}{b^{2}} + \frac{y^{2}}{a^{2}} = 1$ $x^2/b^2 + y^2/a^2 =1$ , a>b
$a^{2} = 25 and b^{2} = 9$ $a^2 =25 and b^2=9$ . Calculate $c^{2} = a^{2} - b^{2} = 25 - 9 = 16$ $c^2 = a^2-b^2= 25-9=16$ . Thus c= 4.

Vertices of the ellipse would lie on the major axis, that is y axis in this case. These can be obtained by putting x=0 in the ellipse equation , so that y= $\pm 5$ $+- 5$ ,

The vertices would thus be (0,5) and (0,-5) and focii would be (0,4) and (0,-4)

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