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Answer 1 · 2015-03-13T09:57:53

Check the basics

We can derive the unit from the basic equations and definitions.
$F = m \cdot a$ $F = m*a$
$F = m \cdot \frac{d}{d t} (v)$ $F = m*d/dt(v)$
$F = m \cdot \frac{d^{2} L}{{d t}^{2}}$ $F = m*(d^2L)/dt^2$
Now we know differentiating adds a unit corresponding to the independent variable. Hence $F = M^{1} L^{1} T^{- 2}$ $F=M^1L^1T^-2$

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