Question #271f2

1 Answer
Stefan V.
Jan 22, 2015

The answer is #DeltaG^@ = +24.5# #"kJ/mol"#.

The standard-state free energy of reaction, or #DeltaG^@#, refers to the free energy of reaction at standard state conditions, and can be calculated using

#DeltaG^@ = DeltaH^@ - T* DeltaS^@#

Again, this is as straighforward as it gets, just plug in your values and solve for #DeltaG^@#.

#DeltaG^@ = "-50.0 kJ/mol" -"298.15 K" * ("-250" "J"/("mol" * "K"))#

#DeltaG^@ = "-50.0 kJ/mol" + "74.5 kJ/mol" = "+24.5 kJ/mol"#

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