Question #658ea

Question

2130 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-01-22T22:30:21

#K=3xx10^5#

#DeltaG=-RTlnK#

#lnK=-(DeltaG)/(RT)#

#lnK=-((-32.5xx10^3)/(8.31xx310))#

#lnK=12.61#

#K=3xx10^5#

Strictly speaking #DeltaG^0# should be under standard conditions. This is at 310K.