Question #091ee

1 Answer
Stefan V.
May 27, 2015

The pH of your solution will be equal to 13.0.

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce sodium cations, #Na^(+)#. and hydroxide anions, #OH^(-)#, according to the following chemical equation

#NaOH_((aq)) -> Na_((aq))^(+) + OH_((aq))^(-)#

http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html

Notice that 1 mole of sodium hydroxide produces 1 mole of #Na^(+)# and 1 mole of #OH^(-)# ions. This means that the concentration of the hydroxide ions will be equal to

#[OH^(-)] = [NaOH] = "0.1 M"#

You can use this concentration to determine the pOH of the solution

#pOH = -log([OH^(-)])#

#pOH = -log(0.1) = 1.0#

Therefore, the pH of the solution will be equal to

#pH_"sol" = 14 - pOH = 14 -1.0 = color(green)(13.0)#

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