Question #524f7

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Question #524f7

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Answer 1 · 2014-12-23T15:00:29

Diatomic oxygen is composed out of two oxygen atoms. Each oxygen atom has a molar weight of $16$ $16$ $g/mol$ $"g/mol"$ , which means that the $O_{2}$ $O_2$ molecule will have a molar weight of $2 \cdot 16 = 32$ $2 * 16 = 32$ $g/mol$ $"g/mol"$ .

One mole is defined as the weight of exactly $6.022 \cdot 10^{23}$ $6.022 * 10^23$ atoms or molecules, depending on the substance.

1 mole of $O$ $O$ has $6.022 \cdot 10^{23}$ $6.022 * 10^23$ atoms of $O$ $O$ and weighs 16 grams.
1 mole of $O_{2}$ $O_2$ has $6.022 \cdot 10^{23}$ $6.022 * 10^23$ molecules of $O_{2}$ $O_2$ and weights 32 grams.

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Question #524f7

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