Question #7c9bd

1 Answer
Stefan V.
Dec 13, 2014

The answer is pH = #11.97#.

The balanced chemical equation is

#KOH_((s)) + H_2O_((l)) -> K_((aq))^+ + OH_((aq))^-#

Since #KOH# is a strong base, it will completely dissociate into #K^+# and #OH^-# ions; this means that the concentration of both #K^+# and #OH^_# will be equal to the starting concentration of #9.28 * 10^-3M#.

We know that pH = #14 - pOH#, which means that we need to determine the pOH first

#pOH = -log([OH^-]) = -log(9.28 * 10^-3) = 2.03#

Therefore, the pH is equal to #pH = 14 - 2.03 = 11.97#

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