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Question #f2762

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Dec 2, 2014

The final temperature is -175.9 Celsius degrees.

#(V_(1))/(T_(1))=(V_2)/T_(2)#

#V_(1)# = 10ml
#T_(1)# = 80 + 273 = 353K

#V_(2)# = 2.75 ml
#T_(2)# is unknown.

#T_(2)=(V_(2)T_(1))/(V_(1))#

#T_2=(2.75xx353)/(10)=97.1K#

#T_2=97.1 - 273 =175.9 # deg Celsius.

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