What mass of propane will produce 4.8 MJ of energy when undergoing complete combustion ?

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Answer 1 · 2014-11-27T22:51:07

95.04g are required.

#C_3H_(8(g))+5O_(2(g))rarr3CO_(2(g))+4H_2O_((g))#

#DeltaH_c=-2219kJ#

#M_r# of #C_3H_8 = (3 xx 12) +(8 xx1)= 44#

So 2219 kJ require 44g

So 1kJ requires 44/2219 = 0.0198g

So 1MJ requires #0.0198xx10^(3)"g"# - this is because there are #10^(3)"kJ"# in #1"MJ"#

So 4.8MJ requires #0.0198 xx10^(3)xx4.8 "g"#

= 95.04g