Question #29a4c
1 Answer
Explanation:
In order to determine the mass of one molecule of
molecule
-> mole-> grams
The conversion factors include:
6.02 xx 10^23 "molecules = 1 mole" " " (this is Avogadro's constant)
and
"1 mole = the molar mass of the molecule"
The molar mass of carbon dioxide,
C = 1 xx "12.01 g/mol" = "12.01 g/mol" O = 2 xx "16.0 g/mol" = "32.0 g/mol"
So
"12.01 g/mol + 32.0 g/mol = 44.01 g/mol"
The conversion is completed as follows:
1 cancel("molecule CO"_2) xx (1 cancel("mole CO"_2)) / (6.02 xx 10^23 cancel("molecules")) xx "44.01 g"/(1 cancel("mole CO"_2))
= 7.31 xx 10^(-23) "g CO"_2
Molecules cancel with molecules and moles cancel with moles
the outcome is the mass in grams.