$5400 is invested, part of it at 11% and part of it at 9%. For a certain year, the total yield is is 546.00. How much was invested at each rate?

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$5400 is invested, part of it at 11% and part of it at 9%. For a certain year, the total yield is is 546.00. How much was invested at each rate?

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Answer 1 · 2018-03-24T22:17:00

$$2400$ invested at $9%$
$$3000$ invested at $11%$

Explanation:

We can divide $$5400$ by letting $5400-x$ be the part invested at $11%$ and the other $x$ is invested at $9%$ . We have the equation
$0.11(5400-x)+0.09x=546$ . Solving for $x$ . We have
$594-0.11x+0.09x=546$
$48=0.02x x = 2400$
Therefore we have
$$2400$ invested at $9%$
$$3000$ invested at $11%$

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$5400 is invested, part of it at 11% and part of it at 9%. For a certain year, the total yield is is 546.00. How much was invested at each rate?

1 Answer

Explanation:

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