Question #2b92d

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Question #2b92d

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Answer 1 · 2015-03-20T06:43:58

You can use a single replacement reaction in which elemental iodine reacts with bromic acid, ${HBrO}_{3}$ $"HBrO"_3$ , to produce iodic acid, ${HIO}_{3}$ $"HIO"_3$ , and elemental bromine. Iodine replaces bromine in single replacement reactions involving halogens.

$I_{2} (s)$ $"I"_2("s")$ + ${2HBrO}_{3} (aq)$ $"2HBrO"_3("aq")$ $\to$ $rarr$ ${2IO}_{3} (aq)$ $"2IO"_3("aq")$ + ${Br}_{2} (l)$ $"Br"_2("l")$

Answer 2 · 2015-03-20T07:01:16

You can use a single replacement reaction in which elemental iodine reacts with bromic acid, ${HBrO}_{3}$ $"HBrO"_3$ , to produce iodic acid, ${HIO}_{3}$ $"HIO"_3$ , and elemental bromine. Iodine replaces bromine in single replacement reactions involving halogens. This reaction reduces the oxidation number for bromine from +5 in the bromic acid to 0 for the elemental bromine.

$I_{2} (s)$ $"I"_2("s")$ + ${2HBrO}_{3} (aq)$ $"2HBrO"_3("aq")$ $\to$ $rarr$ ${2IO}_{3} (aq)$ $"2IO"_3("aq")$ + ${Br}_{2} (l)$ $"Br"_2("l")$

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Question #2b92d

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