# 4790 joules of heat are added to 222 grams of water originally at 27.7 C. What is the final temperature of the water?

##### 2 Answers

If I am correct, you will need to know the equation

#### Explanation:

Here, you are given the values for Q, m and c can be obtained from your textbook. According to mine, the value should be 4.19 J/C.

Note that I let x represent the final temperature. And now, all you have to do is some simple arithmetic and solve for x!

The final answer is 32.8°C

The final temperature is

#### Explanation:

Use the specific heat equation:

**Known**

**Unknown**

**Solution**

Rearrange the equation to isolate

Divide

Now that

Add