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2 NOBr (g) - 2NO (g) + Br2 (g) Given the rate is -2.3 mol NOBr L-1hr-1 when the initial concentration was 6.2 M what is the rate constant k? Assume the reaction is 1st order in [NOBr]

1 Answer

Feb 2, 2015

The value of the rate constant #k=0.37hr^(-1)#

#"NOBrrarr2NO+Br_2#

The first order rate expression is:

#-(d[NOBr])/(dt)=k[NOBr]#

#-(-2.3)=kxx6.2#

#k=2.3/6.2= 0.37hr^(-1)#

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