2 moles of H2O(g), 2.6 moles of N2(g), 2.00 moles of H2(g), and 2.00 moles of NO(g) are in equilibrium in a 2 L container. If a second 1L container with 1 mole of H2(g) is combined with the first, what is the initial reaction quotient?
2 H2O(g) + N2(g) <-----> 2 H2(g) + 2NO(g)
Here is the reaction but I'm completely lost.
2 H2O(g) + N2(g) <-----> 2 H2(g) + 2NO(g)
Here is the reaction but I'm completely lost.
1 Answer
Explanation:
We know that the first container is
And after the
The concentrations of each species at this point are
-
#"H"_2"O"# :#(2.00color(white)(l)"mol")/(color(green)(3)color(white)(l)color(green)("L")) = 0.667M# -
#"N"_2# :#(2.60color(white)(l)"mol")/(color(green)(3)color(white)(l)color(green)("L")) = 0.867M# -
#"H"_2# :#(3.00color(white)(l)"mol")/(color(green)(3)color(white)(l)color(green)("L")) = 1.00M# -
#"NO"# :#(2.00color(white)(l)"mol")/(color(green)(3)color(white)(l)color(green)("L")) = 0.667M#
The reaction quotient expression for this reaction is
Plugging in the above concentrations, our reaction quotient is