How do you solve #log_5x=3#?

2 Answers
Aug 14, 2018

#log_5 x=3 <=>x=5^3=125#

Explanation:

Here ,

#log_5 x=3#

We know that , for #X , YinRR^+ anda inRR^+ -{1}#

#color(red)(log_aX=Y <=>X=a^Y to" Definition"#

#:.log_5 x=3 <=>x=5^3=125#

Aug 14, 2018

#x=125#

Explanation:

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_b x=nhArrx=b^n#

#log_5 x=3rArrx=5^3=125#