How do you solve #-2( x + 4) > 6x - 4#?

1 Answer
Jim G.
Aug 14, 2018

#x< -1/2#

Explanation:

#"distribute bracket on left side"#

#-2x-8>6x-4#

#"subtract "6x" from both sides"#

#-2x-6x-8> -4#

#-8x-8> -4#

#"add 8 to both sides"#

#-8x>4#

#"divide both sides by "-8#

#color(blue)"reversing the symbol as a consequence"#

#x< -1/2#

#x in(-oo,-1/2)larrcolor(blue)"in interval notation"#

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