If kinetic energy of electron is double then its radius becomes?

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Answer 1 · 2018-08-11T06:37:12

$1/sqrt(2)$ times

For,an electron moving round the nucleus in its orbit,its angular momentum is conserved.

That is, $mvr=C$ (where, $m$ is the mass, $v$ is the velocity and $r$ is the radius , $C$ is a constant)

Now,mass of electron being constant we can say, $r prop 1/v$

Now,kinetic energy of an electron can be written as $K=1/2 mv^2$

So, $K prop v^2$

so,if kinetic energy is doubled,its velocity will become $sqrt(2)$ times than the initial.

So,its radius being inversely proportional to its velocity in an orbit,it will be $1/sqrt(2)$ times the initial value!