If kinetic energy of electron is double then its radius becomes?

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Answer 1 · 2018-08-11T06:37:12

#1/sqrt(2)# times

For,an electron moving round the nucleus in its orbit,its angular momentum is conserved.

That is, #mvr=C# (where, #m# is the mass,#v# is the velocity and #r# is the radius , #C# is a constant)

Now,mass of electron being constant we can say, #r prop 1/v#

Now,kinetic energy of an electron can be written as #K=1/2 mv^2#

So, #K prop v^2#

so,if kinetic energy is doubled,its velocity will become #sqrt(2)# times than the initial.

So,its radius being inversely proportional to its velocity in an orbit,it will be #1/sqrt(2)# times the initial value!